Re: [CR]50mph cadence

(Example: Component Manufacturers)

Date: Tue, 12 Jun 2001 13:56:26 -0500 (EST)
From: "Brandon Ives" <monkey37@bluemarble.net>
To: Mark Petry <mpetry@bainbridgeisland.net>
Cc: "Stockwell, Brad" <BRAD.STOCKWELL@mpp.cpii.com>, Classicrendezvous@bikelist.org
Subject: Re: [CR]50mph cadence
In-Reply-To: <039b01c0f36e$3a006370$cc4516ac@Mpetry2k>


207 that's just fast, not superhuman. If you want to see superhuman check out the footage of the Japanese Kerin school in "Bicycle a history of invention" It's room full of these guys on the 12" wide rollers right next to each other doing sprint workouts, I kept thinking about dominos. enjoy, Brandon"monkeyman"Ives

"Nobody can do everything, but if everybody did something everything would get done." Gil Scott-Heron

On Tue, 12 Jun 2001, Mark Petry wrote:
> Yes but...
>
> If he were on the small (42) ring, and in the smallest rear sprocket, 14t,
> then the developed gear length would be 21.19 feet (((42/14)X(27X3.14)/12)
> ...
>
> Yield 207 RPM in a 42/14 to do 50 MPH
>
> markp
>
>
> ----- Original Message -----
> From: "Stockwell, Brad" <BRAD.STOCKWELL@mpp.cpii.com>
> To: <Classicrendezvous@bikelist.org>
> Sent: Tuesday, June 12, 2001 11:09 AM
> Subject: RE: [CR]50mph cadence
>
>
> >
> > "to achieve the 50 mph (much less 60 mph)...a cadence well
> > in excess of 300 rpm given any stock rings available at the time"
> >
> > Actually, with a 53 chainring and an 11 cog, 50mph is
> > achieved at 130 rpm (assuming a 68cm diameter wheel, which is 26.8 inch or
> > 2.23ft; circumference is then 7ft; 53/11 is a gear ratio of 4.8, so we get
> > 33.6 ft/pedal revolution. Then 33.6ft/rev X 130 rev/min = 4368 ft/min =
> > 0.83 miles/min = 49.8 mph). This is not surprising since racers often
> pedal
> > down mountain passes at such high speeds.
> >
> > Brad Stockwell
> > Palo Alto